document.write( "Question 155641: the length of arectangle is 3cm less than four times its width.if the perimeter is 38cm,what is the area of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #114652 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Given:
\n" ); document.write( " $\"W=x\"$
\n" ); document.write( " $\"L=4x-3cm\"$
\n" ); document.write( " $\"P=38cm\"$
\n" ); document.write( "So, $\"P=2%28L%2BW%29\"$
\n" ); document.write( " $\"38=2%284x-3%2Bx%29\"$
\n" ); document.write( " $\"38=8x-6%2B2x\"$
\n" ); document.write( " $\"38%2B6=10x\"$ -----> $\"cross%2844%294.4%2Fcross%2810%29=cross%2810%29x%2Fcross%2810%29\"$
\n" ); document.write( " $\"x=4.4cm\"$ -----------------------------------> Width
\n" ); document.write( " $\"4%284.4%29-3cm=17.6-3=14.6cm\"$ ------------------> Length
\n" ); document.write( " $\"Area=Length%2AWidth\"$
\n" ); document.write( " $\"A=14.6%2A4.4\"$
\n" ); document.write( " $\"A=64.24cm%5E2\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( " \n" ); document.write( "

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