document.write( "Question 155609: Choose the statement that is true about the given quantities:\r
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\n" ); document.write( "\n" ); document.write( "A. The quantity in column A is greater
\n" ); document.write( "B. The quantity in column B is greater
\n" ); document.write( "C. The two quantity are equal
\n" ); document.write( "D. The relationship cannot be determined from the given information
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\n" ); document.write( "\n" ); document.write( "Column A : f(3) where f(x) = 2x -7, if x < = 1\r
\n" ); document.write( "\n" ); document.write( " = -x + 9, if x > 1\r
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\n" ); document.write( "\n" ); document.write( "Column B: f(2) where f(x) = x + 2, if x < 8\r
\n" ); document.write( "\n" ); document.write( " = 3x -3, if x > = 8
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Algebra.Com's Answer #114637 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "f(3) is asking: \"if x=3, then f(3)=? \"\r
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\n" ); document.write( "\n" ); document.write( "Since 3 is greater than 1, this means that we'll use the second equation \"y=-x%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2B9\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3%2B9\" Plug in \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=6\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"f%283%29=6\"\r
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\n" ); document.write( "\n" ); document.write( "f(2) is asking: \"if x=2, then f(2)=? \"\r
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\n" ); document.write( "\n" ); document.write( "Since 2 is less than 8, this means that we'll use the first equation \"y=x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=x%2B2\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=2%2B2\" Plug in \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"f%282%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"f%283%29%3Ef%282%29\", this means that the value of column A is greater than the value of column B. So the answer is A.
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