document.write( "Question 155598: The width of a rectangle is 2 ft less than the length. the area is 8 ft^2. Find the length and the width.\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP!!!
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Algebra.Com's Answer #114634 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Remember: For rectangle,
\n" ); document.write( "\"Area=Length%2AWidth\"----------------------------> working eqn
\n" ); document.write( "Given:
\n" ); document.write( "\"L=unknown=x\"
\n" ); document.write( "\"W=x-2ft\"
\n" ); document.write( "\"A=8ft%5E2\"
\n" ); document.write( "Substitute, \"8=x%2A%28x-2%29\"
\n" ); document.write( "\"8=x%5E2-2x\" ------> \"x%5E2-2x-8=0\"
\n" ); document.write( "BY QUADRATIC: \"a=1\", \"b=-2\", & \"c=-8\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x=%28-%28-2%29%2B-sqrt%28-2%5E2-4%2A1%2A-8%29%29%2F%282%2A1%29\"
\n" ); document.write( "\"x=%28%2B2%2B-sqrt%284%2B32%29%29%2F2\"
\n" ); document.write( "\"x=%282%2B-sqrt%2836%29%29%2F2\"
\n" ); document.write( "\"x=%282%2B-6%29%2F2\"---> 2 values \"%282%2B6%29%2F2=8%2F2=4\",\"%282-6%29%2F2=-4%2F2=-2\"
\n" ); document.write( "USED \"x=4ft\" ----------------> LENGTH
\n" ); document.write( "\"4-2=2ft\" -----------------> WIDTH
\n" ); document.write( "In doubt? Go back working eqn:
\n" ); document.write( "\"8ft%5E2=%284ft%29%282ft%29\"
\n" ); document.write( "\"8ft%5E2=8ft%5E2\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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