document.write( "Question 155567: 8 years ago, Jimmy was three times as old as Anne. In 4 years, Jimmy will be 3/2 of Anne's age. How old is Jimmy now? \n" ); document.write( "
Algebra.Com's Answer #114626 by ankor@dixie-net.com(22740)\"\" \"About 
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Let j = Jimmy's age now
\n" ); document.write( "Let a = Anne's age now
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\"8 years ago, Jimmy was three times as old as Anne.\"
\n" ); document.write( "(j-8) = 3(a-8)
\n" ); document.write( "Smplify
\n" ); document.write( "j - 8 = 3a - 24
\n" ); document.write( "j = 3a - 24 + 8
\n" ); document.write( "j = (3a-16)
\n" ); document.write( ":
\n" ); document.write( "\" In 4 years, Jimmy will be 3/2 of Anne's age.\"
\n" ); document.write( "j + 4 = \"3%2F2\"(a+4)
\n" ); document.write( "Get rid of the denominator, multiply both sides by 2:
\n" ); document.write( "2(j+4) = 3(a+4)
\n" ); document.write( "2j + 8 = 3a + 12
\n" ); document.write( "2j = 3a + 12 - 8
\n" ); document.write( "2j = 3a + 4
\n" ); document.write( ":
\n" ); document.write( " How old is Jimmy now?
\n" ); document.write( "From the 1st equation, substitute (3a-16) for j in the above equation
\n" ); document.write( "2(3a-16) = 3a + 4
\n" ); document.write( "6a - 32 = 3a + 4
\n" ); document.write( "6a - 3a = 4 + 32
\n" ); document.write( "3a = 36
\n" ); document.write( "a = \"36%2F3\"
\n" ); document.write( "a = 12 yrs is Anne's age now
\n" ); document.write( "then
\n" ); document.write( "j = 3(12) - 16 (from the 1st equation)
\n" ); document.write( "j = 36 - 16
\n" ); document.write( "j = 20 yrs is Jimmy's age now
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check our solution in the statement:
\n" ); document.write( "In 4 years, Jimmy will be 3/2 of Anne's age.
\n" ); document.write( "24 = \"3%2F2\" * 16
\n" ); document.write( "24 = 24
\n" ); document.write( ":
\n" ); document.write( "How about this? It it make sense to you?
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