document.write( "Question 155567: 8 years ago, Jimmy was three times as old as Anne. In 4 years, Jimmy will be 3/2 of Anne's age. How old is Jimmy now? \n" ); document.write( "
Algebra.Com's Answer #114626 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let j = Jimmy's age now \n" ); document.write( "Let a = Anne's age now \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( "\"8 years ago, Jimmy was three times as old as Anne.\" \n" ); document.write( "(j-8) = 3(a-8) \n" ); document.write( "Smplify \n" ); document.write( "j - 8 = 3a - 24 \n" ); document.write( "j = 3a - 24 + 8 \n" ); document.write( "j = (3a-16) \n" ); document.write( ": \n" ); document.write( "\" In 4 years, Jimmy will be 3/2 of Anne's age.\" \n" ); document.write( "j + 4 = \n" ); document.write( "Get rid of the denominator, multiply both sides by 2: \n" ); document.write( "2(j+4) = 3(a+4) \n" ); document.write( "2j + 8 = 3a + 12 \n" ); document.write( "2j = 3a + 12 - 8 \n" ); document.write( "2j = 3a + 4 \n" ); document.write( ": \n" ); document.write( " How old is Jimmy now? \n" ); document.write( "From the 1st equation, substitute (3a-16) for j in the above equation \n" ); document.write( "2(3a-16) = 3a + 4 \n" ); document.write( "6a - 32 = 3a + 4 \n" ); document.write( "6a - 3a = 4 + 32 \n" ); document.write( "3a = 36 \n" ); document.write( "a = \n" ); document.write( "a = 12 yrs is Anne's age now \n" ); document.write( "then \n" ); document.write( "j = 3(12) - 16 (from the 1st equation) \n" ); document.write( "j = 36 - 16 \n" ); document.write( "j = 20 yrs is Jimmy's age now \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solution in the statement: \n" ); document.write( "In 4 years, Jimmy will be 3/2 of Anne's age. \n" ); document.write( "24 = \n" ); document.write( "24 = 24 \n" ); document.write( ": \n" ); document.write( "How about this? It it make sense to you? \n" ); document.write( " |