document.write( "Question 155493This question is from textbook Intermediate Algebra
\n" ); document.write( ": Investing. A man invested $14,000, some at 7% and some at 10% annual interest. The annual income from these investments was $1,280. How much did e invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #114617 by checkley77(12844)\"\" \"About 
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.10x+.07(14,000-x)=1,280
\n" ); document.write( ".10x+980-.07x=1,280
\n" ); document.write( ".03x=1,280-980
\n" ); document.write( ".03x=300
\n" ); document.write( "x=300/.03
\n" ); document.write( "x=10,000 invested @ 10%
\n" ); document.write( "14,000-10,000=4,000 invested @ 7%
\n" ); document.write( "Proof:
\n" ); document.write( ".10*10,000+.07*4,000=1,280
\n" ); document.write( "1,000+280=1,280
\n" ); document.write( "1,280=1,280
\n" ); document.write( "
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