document.write( "Question 155493This question is from textbook Intermediate Algebra
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document.write( ": Investing. A man invested $14,000, some at 7% and some at 10% annual interest. The annual income from these investments was $1,280. How much did e invest at each rate? \n" );
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Algebra.Com's Answer #114617 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .10x+.07(14,000-x)=1,280 \n" ); document.write( ".10x+980-.07x=1,280 \n" ); document.write( ".03x=1,280-980 \n" ); document.write( ".03x=300 \n" ); document.write( "x=300/.03 \n" ); document.write( "x=10,000 invested @ 10% \n" ); document.write( "14,000-10,000=4,000 invested @ 7% \n" ); document.write( "Proof: \n" ); document.write( ".10*10,000+.07*4,000=1,280 \n" ); document.write( "1,000+280=1,280 \n" ); document.write( "1,280=1,280 \n" ); document.write( " |