document.write( "Question 155497: (Square root of 2X+3) = (square root of X+2) + 2\r
\n" ); document.write( "\n" ); document.write( "Can you help me solve this? I've already done some work:\r
\n" ); document.write( "\n" ); document.write( "1. I squared both sides of the equation and got: 2X+3 = X+2+(4 square root of X+2) + 4 because I foiled the right side, but I don't think I did it correctly\r
\n" ); document.write( "\n" ); document.write( "2. then, I got: X-3= (4 Square root of X+2) \n" ); document.write( "
Algebra.Com's Answer #114612 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
(Square root of 2X+3) = (square root of X+2) + 2 \r
\n" ); document.write( "\n" ); document.write( "X-3=(4 Square root of X+2) GOOD SO FAR.
\n" ); document.write( "NOW SQUARE BOTH SIDES AGAIN.
\n" ); document.write( "X^2-6X+9=16(X+2)
\n" ); document.write( "X^2-6X+9=16X+32
\n" ); document.write( "X^2-6X-16X+9-32=0
\n" ); document.write( "X^2-22X-23=0
\n" ); document.write( "(X-23)(X+1)=0
\n" ); document.write( "X-23=0
\n" ); document.write( "X=23 ANSWER.
\n" ); document.write( "X+1=0
\n" ); document.write( "X=-1 ANSWER.
\n" ); document.write( "PROOF:
\n" ); document.write( "SQRT(2*23+3)=SQRT(23+2)+2
\n" ); document.write( "SQRT(46+3)=SQRT(25)+2
\n" ); document.write( "SQRT49=5+2
\n" ); document.write( "7=7\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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