document.write( "Question 155544: On the worksheet it shows the equation:
\n" ); document.write( "\"1%2Fz-1%2F2z-1%2F5z=10%2F%28z%2B1%29\" The first thing i tried to do was get rid of the fraction by mutiplying by the LCD, which i figured would be (z)(2z)(5z)(z+1). however it ended up being a jumbled mess and left me very confused and now I have no idea what to do.
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Algebra.Com's Answer #114568 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
you're using the right technique, but your LCD has too many z's - one is enough\r
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\n" ); document.write( "\n" ); document.write( "LCD is (z) times (2), (already have the z), times (5), times (z+1)\r
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\n" ); document.write( "\n" ); document.write( "(10(z+1))-(5(z+1))-(2(z+1))=10(10z) __ 10z+10-5z-5-2z-2=100z __ 3z+3=100z __ 3=97z __ 3/97=z
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