document.write( "Question 155556: please help me solve \"1%2B2%2F%28b-1%29=2%2F%28b%5E2-b%29\". THANK YOU \n" ); document.write( "
Algebra.Com's Answer #114566 by sim9739(6)\"\" \"About 
You can put this solution on YOUR website!
\"1%2B2%2F%28b-1%29=2%2F%28b%5E2-b%29\"
\n" ); document.write( "\"%28%28b-1%29%2B2%29%2F%28b-1%29=2%2F%28b%5E2-b%29\"
\n" ); document.write( "\"%28b%2B1%29%2F%28b-1%29=2%2Fb%2A%28b-1%29\"
\n" ); document.write( "\"b%2B1+=+2%2Fb\"
\n" ); document.write( "\"b%5E2%2Bb+-2=0\"
\n" ); document.write( "\"%28b%2B2%29%28b-1%29+=+0\"
\n" ); document.write( "so b = 1 or b = -2,\r
\n" ); document.write( "\n" ); document.write( "But if b= 1, then the term \"2%2F%28b-1%29\" = 2/0 and it is not defined
\n" ); document.write( "Hence, b=-2
\n" ); document.write( "
\n" );