document.write( "Question 155488: Soybean meal is 16% protein, cornmeal is 8% protein. How many pounds of each should be mixed togeather in order to get a 320 lb mixture that is 14% protein?\r
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Algebra.Com's Answer #114565 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Soybean=240 lb\r
\n" ); document.write( "\n" ); document.write( "Coenmeal=80 lb\r
\n" ); document.write( "\n" ); document.write( "Let x=amount of 16% protein needed
\n" ); document.write( "Then 320-x=amount of 8% protein needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure protein in the 16% mixture (0.16x) plus the amount of pure protein in the 8% mixture (0.08(320-x)) has to equal the amount of pure protein in the final mixture (0.14*320). So our equation to solve is:
\n" ); document.write( "0.16x+ 0.08(320-x)=0.14*320 get rid of parens and simplify\r
\n" ); document.write( "\n" ); document.write( "0.16x+25.6-0.08x=44.8 subtract 25.6 from each side\r
\n" ); document.write( "\n" ); document.write( "0.16x+25.6-25.6-0.08x=44.8-25.6 collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.08x=19.2\r
\n" ); document.write( "\n" ); document.write( "divide each side by 0.08
\n" ); document.write( "x=240 lb-----------------------amount of 16% mixture needed(soybean)\r
\n" ); document.write( "\n" ); document.write( "320-x=320-240=80 lb-------------amount of 8% mixture needed(cornmeal)\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "240*0.16+80*0.08=320*0.14
\n" ); document.write( "38.4+6.4=44.8\r
\n" ); document.write( "\n" ); document.write( "44.8=44.8\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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