document.write( "Question 155554: THE EQUATION |X+1|=3 PRODUCES TWO SOULTIONS X=2 AND X=-4 FOR WHAT VALUES OF
\n" ); document.write( "A AND B WOULD THE EQUATION |X+A|=B PRODUCE TWO SOLUTIONS THAT ARE EQUAL. \n" ); document.write( "

Algebra.Com's Answer #114561 by Edwin McCravy(20060) $\"\"$ $\"About$

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THE EQUATION |X+1|=3 PRODUCES TWO SOULTIONS X=2 AND X=-4 FOR WHAT VALUES OF
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document.write( "The two equations are:\r\n" );
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document.write( "X+A=B     and    X+A=-B\r\n" );
document.write( "  X=B-A            X=-B-A\r\n" );
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document.write( "So the two solutions are B-A and -B-A.\r\n" );
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document.write( "We set those equal to each other:\r\n" );
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document.write( "      B-A=-B-A\r\n" );
document.write( "      B+B=A-A\r\n" );
document.write( "       2B=0\r\n" );
document.write( "        B=0 \r\n" );
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document.write( "So the value of B would be 0.\r\n" );
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document.write( "Substitute in the original:\r\n" );
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document.write( "|X+A|=0\r\n" );
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document.write( " X+A=0\r\n" );
document.write( "   X=-A\r\n" );
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document.write( "So A can be any number, but B can only be 0.\r\n" );
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document.write( "and the one solution would always be X = -A\r\n" );
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document.write( "Edwin

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