document.write( "Question 155529: log(x) + log(2x) = 10 \r
\n" ); document.write( "\n" ); document.write( "Im really confused on this question. Ive been trying this:\r
\n" ); document.write( "\n" ); document.write( "log(x(2x))=10
\n" ); document.write( "log(2x-x^2)=10\r
\n" ); document.write( "\n" ); document.write( "but after that im not sure what to do next. Any help would be great. Thank you!!
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Algebra.Com's Answer #114546 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"Log%28x%29%2BLog%282x%29+=+10\" Apply the \"product rule\" for logarithms.\"Log%28a%29%2BLog%28b%29+=+Log%28a%2Ab%29\"
\n" ); document.write( "\"Log%28x%2A%282x%29%29+=+10\" Simplify the left side.
\n" ); document.write( "\"Log%282x%5E2%29+=+10\" Apply the power rule for logarithms. \"Log%28a%5En%29+=+n%2ALog%28a%29\"
\n" ); document.write( "\"2%2ALog%282x%29+=+10\" Divide both sides by 2.
\n" ); document.write( "\"Log%282x%29+=+5\" Convert to the equivalent exponential form:\"Log%5Bb%5D%28x%29+=+y\"--->\"b%5Ey+=+x\", so...
\n" ); document.write( "\"10%5E5+=+2x\"
\n" ); document.write( "\"100000=+2x\" Divide both sides by 2.
\n" ); document.write( "\"highlight%28x+=+50000%29\"
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