document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23047>Question 23047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11454 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6(t+3)=10t<BR>\n" );
document.write( "6t+18=10t<BR>\n" );
document.write( "18=4t<BR>\n" );
document.write( "t=4.5<BR>\n" );
document.write( "hence, 4.5hours will pass. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );