document.write( "Question 155515: the length of a rectangle is twice the width. the perimeter is 48 in. find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #114536 by oscargut(2103) $\"\"$ $\"About$

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x=length
\n" ); document.write( "y=width
\n" ); document.write( "the length of a rectangle is twice the width
\n" ); document.write( "then x=2y
\n" ); document.write( "the perimeter is 48 in.
\n" ); document.write( "then 2(x+y)=48 then x+y=24\r
\n" ); document.write( "\n" ); document.write( " $\"x=2y\"$
\n" ); document.write( " $\"x%2By=24\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2y%2By=24\"$ then $\"3y=24\"$ then $\"y=8\"$
\n" ); document.write( " $\"x=24-8=16\"$
\n" ); document.write( "Answer: length is 16 in and width is 8 in \n" ); document.write( "

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