document.write( "Question 155522: Please help me solve: $\"+sqrt%285x%2B1%29+=+x-4+\"$ \n" ); document.write( "

Algebra.Com's Answer #114534 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( " $\"sqrt%285x%2B1%29+=+x-4\"$ Square both sides of the equation.
\n" ); document.write( " $\"5x%2B1+=+x%5E2-8x%2B16\"$ Subtract 5x from both sides.
\n" ); document.write( " $\"1+=+x%5E2-13x%2B16\"$ Subtract 1 from both sides.
\n" ); document.write( " $\"x%5E2-13x%2B15+=+0\"$ This is not factorable so use the quadratic formula: $\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"$ Here, a = 1, b = -13, and c = 15, so make the appropriate substitutions:
\n" ); document.write( " $\"x+=+%28-%28-13%29%2B-sqrt%28%28-13%29%5E2-4%281%29%2815%29%29%29%2F2%281%29\"$ Simplify.
\n" ); document.write( " $\"x+=+%2813%2B-sqrt%28169-60%29%29%2F2\"$
\n" ); document.write( " $\"x+=+%2813%2B-sqrt%28109%29%29%2F2\"$
\n" ); document.write( " $\"x+=+%2813%2Bsqrt%28109%29%29%2F2\"$ or $\"x+=+%2813-sqrt%28109%29%29%2F2\"$ \n" ); document.write( "

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