document.write( "Question 155517: Please help me answer this: abs(4a+7)<13
\n" ); document.write( "I got -5\n" ); document.write( "

Algebra.Com's Answer #114532 by stanbon(75887)\"\" \"About 
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abs(4a+7)<13
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\n" ); document.write( "Solve the EQUALITY:
\n" ); document.write( "4a+7 = 13 or 4a+7 = -13
\n" ); document.write( "a = 3/2 or a = -5
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\n" ); document.write( "Draw a Number line and plot the points a = -5 and 3/2
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\n" ); document.write( "Check a value from each of resulting three intervals in the INEQUALITY
\n" ); document.write( "to see where the solution set is.
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\n" ); document.write( "Let a = -6, then |4*-6+7| <13; false, so no solutions in (-inf,-5)
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\n" ); document.write( "Let a = 0, then |4*0+7} < 13 ; true, so solutions in (-5,3/2)
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\n" ); document.write( "Let a = 2 then |4*2+7| < 13 ; false, so no solutions in (3/2,+inf)
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\n" ); document.write( "Final Answer: -5 < a < 3/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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