document.write( "Question 155475: The measure of a supplement of an angle is 12 degrees greater then 3 times the measure of a complement. Find the measure of the angle. \n" ); document.write( "

Algebra.Com's Answer #114508 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's bisect the problem carefully.
\n" ); document.write( " First illustration:
\n" ); document.write( " $\"A\"$ and $\"B\"$ are supplementary angles, so $\"A%2BB=180\"$ -----> eqn 1
\n" ); document.write( "It shows $\"B\"$ is a supplement of $\"A\"$ and a $\"highlight%28condition%29\"$ exist that the supplement which is $\"B\"$ , is 12 degrees greater than 3 times the complement.
\n" ); document.write( "2nd illustration:
\n" ); document.write( "We make again $\"A\"$ and $\"B\"$ complementary angles this time, so
\n" ); document.write( " $\"A%2BB=90\"$ ----> eqn 2. we make $\"A\"$ a complement of $\"B\"$ . To show the condition on the 1st illustration: $\"highlight%28B=12%2B%283A%29%29\"$ ----> 12 greater than 3 times the complement, being $\"A\"$ a complement of $\"B\"$ right?
\n" ); document.write( "Substitute the $\"highlight%28condition%29\"$ to eqn 1:
\n" ); document.write( " $\"A%2B12%2B3A=180\"$
\n" ); document.write( " $\"4A=180-12=168\"$
\n" ); document.write( " $\"cross%284%29A%2Fcross%284%29=cross%28168%2942%2Fcross%284%29\"$
\n" ); document.write( " $\"A=42degrees\"$
\n" ); document.write( "For $\"B\"$ in question via eqn 1: $\"42%2BB=180\"$
\n" ); document.write( " $\"B=180-42=138degrees\"$
\n" ); document.write( "To check, go back to the $\"highlight%28condition%29\"$ :
\n" ); document.write( " $\"B=12%2B%283A%29\"$
\n" ); document.write( " $\"138=12%2B%283%2A42%29\"$
\n" ); document.write( " $\"138=12%2B126\"$
\n" ); document.write( " $\"138deg=138deg\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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