document.write( "Question 155469: This is totally confusing to me, how do you set this up and solve this problem?\r
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document.write( "Flying agains the jet stream a jet travels 4200 km in 5 hours. flying wih the jetstream, the same jet travels 10620 km in 9 hours. What is the speed of the jet still in the air, and what is the speed of the jet stream? \n" );
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Algebra.Com's Answer #114488 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! You must apply the distance formula: \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "Let x = speed of jet stream \n" ); document.write( "and y = speed of the jet in still air \n" ); document.write( ". \n" ); document.write( "Since we have two unknowns, we'll need two equations. \n" ); document.write( ". \n" ); document.write( "From:\"Flying against the jet stream a jet travels 4200 km in 5 hours.\" we get equation 1 \n" ); document.write( "5(y-x) = 4200 \n" ); document.write( ". \n" ); document.write( "From:\"flying with the jet stream, the same jet travels 10620 km in 9 hours.\" we get equation 2 \n" ); document.write( "9(y+x) = 10620 \n" ); document.write( ". \n" ); document.write( "Solve equation 1 for y: \n" ); document.write( "5(y-x) = 4200 \n" ); document.write( "y-x = 840 \n" ); document.write( "y = 840+x \n" ); document.write( ". \n" ); document.write( "Using the above definition of 'y', substitute it into equation 2 and solve for 'x': \n" ); document.write( "9(y+x) = 10620 \n" ); document.write( "9(840+x+x) = 10620 \n" ); document.write( "9(840+2x) = 10620 \n" ); document.write( "840+2x = 1180 \n" ); document.write( "2x = 340 \n" ); document.write( "x = 170 mph (speed of jet stream) \n" ); document.write( ". \n" ); document.write( "Using the above definition of 'x', substitute it into equation 1 and solve for y: \n" ); document.write( "5(y-x) = 4200 \n" ); document.write( "5(y-170) = 4200 \n" ); document.write( "y-170 = 840 \n" ); document.write( "y = 1010 mph (speed of jet in still air) \n" ); document.write( " |