document.write( "Question 155447This question is from textbook College Algerbra in Context
\n" ); document.write( ": I am not sure if this belongs here or not.
\n" ); document.write( "My question:\r
\n" ); document.write( "\n" ); document.write( "How do you solve or what meathod do you use to slove:
\n" ); document.write( "(x+h)^2\r
\n" ); document.write( "\n" ); document.write( "I thought the answer would be:
\n" ); document.write( "x^2+h^2\r
\n" ); document.write( "\n" ); document.write( "However, the answer is:
\n" ); document.write( "x^2+2xh+H^2\r
\n" ); document.write( "\n" ); document.write( "Why is the 2xh in the answer?
\n" ); document.write( "And how do you come to get that answer?
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Algebra.Com's Answer #114480 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2Bh%29%5E2\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bh%29%28x%2Bh%29\" Expand. Remember something like \"A%5E2=A%2AA\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29%2Bh%29%28highlight%28x%29%2Bh%29\" Multiply the First terms:\"%28x%29%2A%28x%29=x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29%2Bh%29%28x%2Bhighlight%28h%29%29\" Multiply the Outer terms:\"%28x%29%2A%28h%29=xh\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28h%29%29%28highlight%28x%29%2Bh%29\" Multiply the Inner terms:\"%28h%29%2A%28x%29=hx\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28h%29%29%28x%2Bhighlight%28h%29%29\" Multiply the Last terms:\"%28h%29%2A%28h%29=h%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bxh%2Bhx%2Bh%5E2\" Now collect every term to make a single expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2xh%2Bh%5E2\" Now combine like terms. Note: the only \"like\" terms are \"xh\" and \"hx\" (which is just the reverse of the first expression). So this means that \"xh%2Bhx=xh%2Bxh=2xh\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"%28x%2Bh%29%5E2\" foils and simplifies to \"x%5E2%2B2xh%2Bh%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x%2Bh%29%5E2=x%5E2%2B2xh%2Bh%5E2\"
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