document.write( "Question 155394: I believe this is a quadratic equation: The question is: given that (x-3) and (x+4) are factors of x^3 + 6x^2-7x-60, I need to find a third first degree factor and then find the factor. I tried grouping (x^ + 6x^) - (7x + 60) I could factor x^ out of the first grouping but I can't seem to find a common factor out of the 2nd grouping. \n" ); document.write( "
Algebra.Com's Answer #114440 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
x^3 + 6x^2-7x-60,(x-3) and (x+4)
\n" ); document.write( "-------------
\n" ); document.write( "X-3
\n" ); document.write( "X+4 MULTIPLY
\n" ); document.write( "----------
\n" ); document.write( "X^2-3X+4X-12=X^2+X-12
\n" ); document.write( "NOW DIVIDE THE X^3 EQUATION BY THIS PRODUCT TO GET THE THIRD FACTOR:
\n" ); document.write( "------------------X+5 ANSWER FOR THE THIRD FACTOR.
\n" ); document.write( "---------_________________
\n" ); document.write( "X^2+X-12 )X^3+6X^2-7X-60
\n" ); document.write( "**********X^3+X^2-12X
\n" ); document.write( "**********-------------
\n" ); document.write( "**************5X^2+5X-60
\n" ); document.write( "**************5X^2+5X-60
\n" ); document.write( "**************-----------
\n" ); document.write( "**************0+0+0
\n" ); document.write( "PROOF:
\n" ); document.write( "X^2+X-12
\n" ); document.write( "X+5 MULTIPLY
\n" ); document.write( "----------
\n" ); document.write( "X^3+X^2-12X+5X^2+5X-60
\n" ); document.write( "X^3+6X^2-7X-60
\n" ); document.write( " \n" ); document.write( "
\n" );