document.write( "Question 23008: i have a couple
\n" ); document.write( " 1. 76.26 is 23%more than what?
\n" ); document.write( " 2. 162 is 3.6%of what?
\n" ); document.write( " 3. Davids savingsaccount earns 2.4%APR. How long does it take for his money to double
\n" ); document.write( "
\n" ); document.write( " please show me how to do these problems
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Algebra.Com's Answer #11444 by stanbon!(97)\"\" \"About 
You can put this solution on YOUR website!
1. Let \"x\" be the amount you are looking for.
\n" ); document.write( "Then x+0.23x = 76.26
\n" ); document.write( " 1.23x = 76.26
\n" ); document.write( " x = 76.26/1.23 = 62
\n" ); document.write( "The amount you are looking for is 62
\n" ); document.write( "2. Let \"x\" be your \"what\".
\n" ); document.write( "Then 3.6%(x)= 162
\n" ); document.write( " 0.036x = 162
\n" ); document.write( " x = 162/0.036= 4500
\n" ); document.write( "3. Formula for simple interest is A=P(1+r)^n
\n" ); document.write( " A is the amount you have after some ti024me.
\n" ); document.write( " P is the amount you started with.
\n" ); document.write( " r is the annual rate of interest
\n" ); document.write( " n is the number of years you let the money grow.
\n" ); document.write( "In your case A = 2P because it doubled.
\n" ); document.write( "EQUATION:
\n" ); document.write( " 2P = P(1+0.024)^n
\n" ); document.write( " 2 = 1.024^n
\n" ); document.write( "Take the log or ln of both sides to get
\n" ); document.write( " log2 = n(log 1.024)
\n" ); document.write( " n = [log 2]/[log 1.024]
\n" ); document.write( " n = 29.23 years.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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