document.write( "Question 23008: i have a couple
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document.write( " 1. 76.26 is 23%more than what?
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document.write( " 2. 162 is 3.6%of what?
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document.write( " 3. Davids savingsaccount earns 2.4%APR. How long does it take for his money to double
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document.write( " please show me how to do these problems \n" );
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Algebra.Com's Answer #11444 by stanbon!(97) ![]() You can put this solution on YOUR website! 1. Let \"x\" be the amount you are looking for. \n" ); document.write( "Then x+0.23x = 76.26 \n" ); document.write( " 1.23x = 76.26 \n" ); document.write( " x = 76.26/1.23 = 62 \n" ); document.write( "The amount you are looking for is 62 \n" ); document.write( "2. Let \"x\" be your \"what\". \n" ); document.write( "Then 3.6%(x)= 162 \n" ); document.write( " 0.036x = 162 \n" ); document.write( " x = 162/0.036= 4500 \n" ); document.write( "3. Formula for simple interest is A=P(1+r)^n \n" ); document.write( " A is the amount you have after some ti024me. \n" ); document.write( " P is the amount you started with. \n" ); document.write( " r is the annual rate of interest \n" ); document.write( " n is the number of years you let the money grow. \n" ); document.write( "In your case A = 2P because it doubled. \n" ); document.write( "EQUATION: \n" ); document.write( " 2P = P(1+0.024)^n \n" ); document.write( " 2 = 1.024^n \n" ); document.write( "Take the log or ln of both sides to get \n" ); document.write( " log2 = n(log 1.024) \n" ); document.write( " n = [log 2]/[log 1.024] \n" ); document.write( " n = 29.23 years.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |