document.write( "Question 155354: An amount of money is invested at 4% annual simple interest, and twice that amount is invested at 5%. The total annual interest is $112. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #114438 by checkley77(12844)\"\" \"About 
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.04X+.05*2X=112
\n" ); document.write( ".04X+.10X=112
\n" ); document.write( ".14X=112
\n" ); document.write( ".14X=112
\n" ); document.write( "X=112/.14
\n" ); document.write( "X=800 INVESTED @ 4%
\n" ); document.write( "2*800=1,600 INVESTED @5%
\n" ); document.write( "PROOF:
\n" ); document.write( ".04*800+.05*1,600=112
\n" ); document.write( "32+80=112
\n" ); document.write( "112=112
\n" ); document.write( "
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