document.write( "Question 155354: An amount of money is invested at 4% annual simple interest, and twice that amount is invested at 5%. The total annual interest is $112. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #114438 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .04X+.05*2X=112 \n" ); document.write( ".04X+.10X=112 \n" ); document.write( ".14X=112 \n" ); document.write( ".14X=112 \n" ); document.write( "X=112/.14 \n" ); document.write( "X=800 INVESTED @ 4% \n" ); document.write( "2*800=1,600 INVESTED @5% \n" ); document.write( "PROOF: \n" ); document.write( ".04*800+.05*1,600=112 \n" ); document.write( "32+80=112 \n" ); document.write( "112=112 \n" ); document.write( " |