document.write( "Question 155358: In 1920, the record for a certain race was 46.8 sec. In 1980, the record was 45.6 sec. Let R(t) + the record in the race and t = the number of years since 1920.
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document.write( "a) find a linear function that fits the data.
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document.write( "b) What is the predicted record for 2003?
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document.write( "c) What is the predicted record for 2006?
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document.write( "In what year will the predicted record be 45.0 sec? \n" );
document.write( "
Algebra.Com's Answer #114423 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! In 1920, the record for a certain race was 46.8 sec. In 1980, the record was 45.6 sec. Let R(t)= the record in the race and t = the number of years since 1920. \n" ); document.write( "a) find a linear function that fits the data. \n" ); document.write( "b) What is the predicted record for 2003? \n" ); document.write( "c) What is the predicted record for 2006? \n" ); document.write( "In what year will the predicted record be 45.0 sec?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R(t)=record \n" ); document.write( "t=# years since 1920\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 1920, the record for a certain race was 46.8 sec. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R(0)=46.8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 1980, the record was 45.6 sec.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R(60)=45.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=f(x) \n" ); document.write( "y=mx+b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Points: \n" ); document.write( "(0,46.8) \n" ); document.write( "(60,45.6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "slope= (45.6-46.8)/(60-0)= -1.2/60 or -1/50\r \n" ); document.write( "\n" ); document.write( "y=(-1/50)x + b. \n" ); document.write( "46.8=(-1/50)0+b \n" ); document.write( "46.8=b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a) find a linear function that fits the data.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)=(-1/50)x+46.8 \n" ); document.write( "--------------------------------------------------------- \n" ); document.write( "b) What is the predicted record for 2003? \n" ); document.write( "x=2003-1920 \n" ); document.write( "x=83\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(83)=(-1/50)83+46.8 \n" ); document.write( "f(83)=45.14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "45.14 \n" ); document.write( "--------------------------------------------------------- \n" ); document.write( "c) What is the predicted record for 2006?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=2006-1920 \n" ); document.write( "x=86 \n" ); document.write( "f(86)=(-1/50)86+46.8 \n" ); document.write( "f(86)=45.08\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "45.08 \n" ); document.write( "--------------------------------------------------------- \n" ); document.write( "In what year will the predicted record be 45.0 sec?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)=45 \n" ); document.write( "(-1.2/60)x+46.8=45 \n" ); document.write( "(-1.2/60)x=-1.8 \n" ); document.write( "x=90\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1920+90=2010\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2010 \n" ); document.write( " |