document.write( "Question 155358: In 1920, the record for a certain race was 46.8 sec. In 1980, the record was 45.6 sec. Let R(t) + the record in the race and t = the number of years since 1920.
\n" ); document.write( "a) find a linear function that fits the data.
\n" ); document.write( "b) What is the predicted record for 2003?
\n" ); document.write( "c) What is the predicted record for 2006?
\n" ); document.write( "In what year will the predicted record be 45.0 sec?
\n" ); document.write( "

Algebra.Com's Answer #114423 by mangopeeler07(462)\"\" \"About 
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In 1920, the record for a certain race was 46.8 sec. In 1980, the record was 45.6 sec. Let R(t)= the record in the race and t = the number of years since 1920.
\n" ); document.write( "a) find a linear function that fits the data.
\n" ); document.write( "b) What is the predicted record for 2003?
\n" ); document.write( "c) What is the predicted record for 2006?
\n" ); document.write( "In what year will the predicted record be 45.0 sec?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R(t)=record
\n" ); document.write( "t=# years since 1920\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In 1920, the record for a certain race was 46.8 sec. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R(0)=46.8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In 1980, the record was 45.6 sec.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R(60)=45.6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y=f(x)
\n" ); document.write( "y=mx+b\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Points:
\n" ); document.write( "(0,46.8)
\n" ); document.write( "(60,45.6)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "slope= (45.6-46.8)/(60-0)= -1.2/60 or -1/50\r
\n" ); document.write( "\n" ); document.write( "y=(-1/50)x + b.
\n" ); document.write( "46.8=(-1/50)0+b
\n" ); document.write( "46.8=b\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a) find a linear function that fits the data.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f(x)=(-1/50)x+46.8
\n" ); document.write( "---------------------------------------------------------
\n" ); document.write( "b) What is the predicted record for 2003?
\n" ); document.write( "x=2003-1920
\n" ); document.write( "x=83\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f(83)=(-1/50)83+46.8
\n" ); document.write( "f(83)=45.14\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "45.14
\n" ); document.write( "---------------------------------------------------------
\n" ); document.write( "c) What is the predicted record for 2006?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x=2006-1920
\n" ); document.write( "x=86
\n" ); document.write( "f(86)=(-1/50)86+46.8
\n" ); document.write( "f(86)=45.08\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "45.08
\n" ); document.write( "---------------------------------------------------------
\n" ); document.write( "In what year will the predicted record be 45.0 sec?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f(x)=45
\n" ); document.write( "(-1.2/60)x+46.8=45
\n" ); document.write( "(-1.2/60)x=-1.8
\n" ); document.write( "x=90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1920+90=2010\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2010
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\n" );