document.write( "Question 155379: 4. The Hudson River flows at a rate of 3 miles per hour. A patrol boat travels 60 miles upriver, and returns in a total time of 9 hours. What is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #114416 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 4\r
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\n" ); document.write( "\n" ); document.write( "Let x = speed of boat in still water
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\n" ); document.write( "\"d=rt\" Start with the distance-rate-time formula
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\n" ); document.write( "\"60=%28x-3%29t\" Plug in \"d=60\" and \"r=x-3\". This equation represents the upstream journey
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\n" ); document.write( "\n" ); document.write( "\"60%2F%28x-3%29=t\" Divide both sides by \"x-3\" to isolate \"t\"
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\n" ); document.write( "\n" ); document.write( "So the expression for the time it takes to go upstream can be represented by the expression \"60%2F%28x-3%29\"
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\n" ); document.write( "\"60=%28x%2B3%29t\" Plug in \"d=60\" and \"r=x%2B3\". This equation represents the downstream journey
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\n" ); document.write( "\"60%2F%28x%2B3%29=t\" Divide both sides by \"x%2B3\" to isolate \"t\"
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\n" ); document.write( "So the expression for the time it takes to go downstream can be represented by the expression \"60%2F%28x%2B3%29\"
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\n" ); document.write( "\n" ); document.write( "Now simply add the two time expressions to get: \"60%2F%28x-3%29%2B60%2F%28x%2B3%29\"
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\n" ); document.write( "\n" ); document.write( "\"60%2F%28x-3%29%2B60%2F%28x%2B3%29=9\" Now set that expression equal to the total time of 9 hours
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\n" ); document.write( "\"60%28x%2B3%29%2B60%28x-3%29=9%28x%2B3%29%28x-3%29\" Multiply every term by the LCD \"%28x%2B3%29%28x-3%29\" to clear the denominators
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\n" ); document.write( "\"60%28x%2B3%29%2B60%28x-3%29=9%28x%5E2-9%29\" FOIL
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\n" ); document.write( "\"60x%2B180%2B60x-180=9x%5E2-81\" Distribute
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\n" ); document.write( "\"60x%2B180%2B60x-180-9x%5E2%2B81=0\" Subtract \"9x%5E2\" from both sides. Add \"81\" to both sides.
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\n" ); document.write( "\n" ); document.write( "\"-9x%5E2%2B120x%2B81=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=-9\", \"b=120\", and \"c=81\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28120%29+%2B-+sqrt%28+%28120%29%5E2-4%28-9%29%2881%29+%29%29%2F%282%28-9%29%29\" Plug in \"a=-9\", \"b=120\", and \"c=81\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+14400-4%28-9%29%2881%29+%29%29%2F%282%28-9%29%29\" Square \"120\" to get \"14400\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+14400--2916+%29%29%2F%282%28-9%29%29\" Multiply \"4%28-9%29%2881%29\" to get \"-2916\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+14400%2B2916+%29%29%2F%282%28-9%29%29\" Rewrite \"sqrt%2814400--2916%29\" as \"sqrt%2814400%2B2916%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+17316+%29%29%2F%282%28-9%29%29\" Add \"14400\" to \"2916\" to get \"17316\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+17316+%29%29%2F%28-18%29\" Multiply \"2\" and \"-9\" to get \"-18\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+6%2Asqrt%28481%29%29%2F%28-18%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120%2B6%2Asqrt%28481%29%29%2F%28-18%29\" or \"x+=+%28-120-6%2Asqrt%28481%29%29%2F%28-18%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%28-120%2B6%2Asqrt%28481%29%29%2F%28-18%29\" or \"x+=+%28-120-6%2Asqrt%28481%29%29%2F%28-18%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=-0.644\" or \"x=13.977\" \r
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\n" ); document.write( "\n" ); document.write( "Since a negative speed doesn't make sense in this problem, this means that the only solution is \"x=13.977\" \r
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\n" ); document.write( "\n" ); document.write( "So the speed of the boat in still water is approximately 13.98 mph (rounded to the nearest hundredth).
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