document.write( "Question 155352: Stella’s Catering is planning a wedding\r
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document.write( "reception. The bride and groom would like to serve\r
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document.write( "a nut mixture containing 25% peanuts. Stella has\r
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document.write( "available mixtures that are either 40% or 10% peanuts.\r
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document.write( "How much of each type should be mixed to get a 10-lb\r
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document.write( "mixture that is 25% peanuts?\r
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Algebra.Com's Answer #114401 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The bride and groom would like to serve \n" ); document.write( "a nut mixture containing 25% peanuts. \n" ); document.write( "Stella has available mixtures that are \n" ); document.write( "either 40% or 10% peanuts. \n" ); document.write( "How much of each type should be mixed to get a 10-lb \n" ); document.write( "mixture that is 25% peanuts? \n" ); document.write( "------------------------------------------------- \n" ); document.write( "Amt. of 40% mix = \"x\" lbs. ; Amt of peanuts in it = 0.40x lbs. \n" ); document.write( "-------------------------- \n" ); document.write( "Amt. of 10% mix = \"10-x\" lbs; Amt. of peanuts in it = 0.10(10-x) = 1-0.1x lbs \n" ); document.write( "---------------------------- \n" ); document.write( "Amt of 25% mis = 10 lbs ; Amt. of peanuts in it = 0.25(10) = 2.5 lbs \n" ); document.write( "=========================== \n" ); document.write( "EQUATION: \n" ); document.write( "peanuts + peanuts = peanuts \n" ); document.write( "0.40x + 1 - 0.1x = 2.5 \n" ); document.write( "0.3x = 1.5 \n" ); document.write( "x = 5 lbs (amt. of 40% nuts in the final mixture) \n" ); document.write( "10-x = 5 lbs (amt of 10% nuts in the final mixture) \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |