document.write( "Question 155352: Stella’s Catering is planning a wedding\r
\n" ); document.write( "\n" ); document.write( "reception. The bride and groom would like to serve\r
\n" ); document.write( "\n" ); document.write( "a nut mixture containing 25% peanuts. Stella has\r
\n" ); document.write( "\n" ); document.write( "available mixtures that are either 40% or 10% peanuts.\r
\n" ); document.write( "\n" ); document.write( "How much of each type should be mixed to get a 10-lb\r
\n" ); document.write( "\n" ); document.write( "mixture that is 25% peanuts?\r
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Algebra.Com's Answer #114401 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The bride and groom would like to serve
\n" ); document.write( "a nut mixture containing 25% peanuts.
\n" ); document.write( "Stella has available mixtures that are
\n" ); document.write( "either 40% or 10% peanuts.
\n" ); document.write( "How much of each type should be mixed to get a 10-lb
\n" ); document.write( "mixture that is 25% peanuts?
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\n" ); document.write( "Amt. of 40% mix = \"x\" lbs. ; Amt of peanuts in it = 0.40x lbs.
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\n" ); document.write( "Amt. of 10% mix = \"10-x\" lbs; Amt. of peanuts in it = 0.10(10-x) = 1-0.1x lbs
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\n" ); document.write( "Amt of 25% mis = 10 lbs ; Amt. of peanuts in it = 0.25(10) = 2.5 lbs
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\n" ); document.write( "EQUATION:
\n" ); document.write( "peanuts + peanuts = peanuts
\n" ); document.write( "0.40x + 1 - 0.1x = 2.5
\n" ); document.write( "0.3x = 1.5
\n" ); document.write( "x = 5 lbs (amt. of 40% nuts in the final mixture)
\n" ); document.write( "10-x = 5 lbs (amt of 10% nuts in the final mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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