document.write( "Question 155292: Solve the equation. Check for extraneous solutions.
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document.write( "sqaure root of x+3 = sqaure root of 2x-7 \n" );
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Algebra.Com's Answer #114398 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! sqaure root of x+3 = sqaure root of 2x-7 \n" ); document.write( "sqrt(x+3)=sqrt(2x-7)squaring both sides we get: \n" ); document.write( "x+3=2x-7 \n" ); document.write( "x-2x=-7-3 \n" ); document.write( "-x=-10 \n" ); document.write( "x=10 answer. \n" ); document.write( "Proof: \n" ); document.write( "sqrt(10+3)=sqrt(2*10-7) \n" ); document.write( "sqrt13=sqrt(20-7) \n" ); document.write( "sqrt13=sqrt13\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |