document.write( "Question 155292: Solve the equation. Check for extraneous solutions.
\n" ); document.write( "sqaure root of x+3 = sqaure root of 2x-7
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Algebra.Com's Answer #114398 by checkley77(12844)\"\" \"About 
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sqaure root of x+3 = sqaure root of 2x-7
\n" ); document.write( "sqrt(x+3)=sqrt(2x-7)squaring both sides we get:
\n" ); document.write( "x+3=2x-7
\n" ); document.write( "x-2x=-7-3
\n" ); document.write( "-x=-10
\n" ); document.write( "x=10 answer.
\n" ); document.write( "Proof:
\n" ); document.write( "sqrt(10+3)=sqrt(2*10-7)
\n" ); document.write( "sqrt13=sqrt(20-7)
\n" ); document.write( "sqrt13=sqrt13\r
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