document.write( "Question 155348This question is from textbook College Algebra
\n" ); document.write( ": Please help me solve this. I need to put it in standard form then solve for x using the quadratic equation which should give me a complex number as an answer. The problem is:\"x%5E3-8=0\". Thanks. \n" ); document.write( "
Algebra.Com's Answer #114397 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Notice that your equation:
\n" ); document.write( "\"x%5E3-8=0\"
\n" ); document.write( "is a \"difference of two cubes\"
\n" ); document.write( "That is, both terms have cube roots:
\n" ); document.write( "the cube root of x^3 is x
\n" ); document.write( "the cube root of 8^3 is 2
\n" ); document.write( ".
\n" ); document.write( "This site describes these \"special cases\":
\n" ); document.write( "http://www.purplemath.com/modules/specfact2.htm
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\n" ); document.write( "Bottom-line:
\n" ); document.write( "If you see a situation of a \"difference of two cubes\", you can factor thus:
\n" ); document.write( "a^3 – b^3 = (a – b)(a^2 + ab + b^2)
\n" ); document.write( ".
\n" ); document.write( "In our case:
\n" ); document.write( "a is x
\n" ); document.write( "b is 2
\n" ); document.write( ".
\n" ); document.write( "Therefore, we can rewrite:
\n" ); document.write( "\"x%5E3-8=0\"
\n" ); document.write( "as
\n" ); document.write( "\"%28x-2%29%28x%5E2+%2B+2x+%2B+2%5E2%29=0\"
\n" ); document.write( "\"%28x-2%29%28x%5E2+%2B+2x+%2B+4%29=0\"
\n" ); document.write( ".
\n" ); document.write( "Finally, to solve, we set each factor on the left to zero:
\n" ); document.write( "First term:
\n" ); document.write( "(x-2) = 0
\n" ); document.write( "x = 2 (Here's one \"real\" solution)
\n" ); document.write( ".
\n" ); document.write( "Second term:
\n" ); document.write( "(x^2 + 2x + 4)=0
\n" ); document.write( "Here's where we need to apply the \"quadratic equation\":
\n" ); document.write( "Note: you will find that there are no real solutions, only 2 imaginary ones:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B4+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A4=-12\".
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\n" ); document.write( " The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

\n" ); document.write( "
\n" ); document.write( " In the field of imaginary numbers, the square root of -12 is + or - \"sqrt%28+12%29+=+3.46410161513775\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B4+%29\"

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