document.write( "Question 12493: Please help me solve this problem: Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarters. How many of each coin does he have?
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Algebra.Com's Answer #11438 by stanbon!(97) ![]() You can put this solution on YOUR website! Let number of nickels be \"x\". \n" ); document.write( "Then number of quarters is \"x-11\" \n" ); document.write( "And number of dimes is \"6(x-11)\" = \"6x-66\" \n" ); document.write( "Value of nickels is (5)x cents \n" ); document.write( "Value of quarters is (25)(x-11)= 25x-275 cents \n" ); document.write( "And Value of dimes is (10)(6x-11)= 60x-110 cents \n" ); document.write( "EQUATION: \n" ); document.write( "Value of nickels + Value of dimes + Value of quarters = 1765 cents \n" ); document.write( " 5x + 25x-275 + 60x-110 = 1765 \n" ); document.write( " 90 x = 2150 \n" ); document.write( " x = 23.89... (number of nickels??????) \n" ); document.write( "Answer doesn't nake sense since you can't have 23.89 nickels.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |