document.write( "Question 155265: solve by completing the square\r
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document.write( "2x^2+5-1=0\r
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document.write( "The solution are/is x= \n" );
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Algebra.Com's Answer #114361 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! solve by completing the square \n" ); document.write( "2x^2+5x-1=0 \n" ); document.write( "2x^2 + 5x = 1 \n" ); document.write( "2(x^2 + (5/2)x + (5/4)^2) = 1 + 2(5/4)^2\r \n" ); document.write( "\n" ); document.write( "2(x+(5/4))^2 = 1 + 2(25/16) = 1 + (25/8) = 33/8\r \n" ); document.write( "\n" ); document.write( "(x+(5/4))^2 = 33/16\r \n" ); document.write( "\n" ); document.write( "Take the square root: \n" ); document.write( "x+(5/4) = [sqrt33]/4 or x+(5/4) = -[sqrt33]/4\r \n" ); document.write( "\n" ); document.write( "x = [-5+sqrt(33)]/4 or x = [-5-sqrt(33)]/4 \n" ); document.write( "============================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |