document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155253>Question 155253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a trangle is 13.5 square meters. Find the base and height of the rectangle if its height is 6 meters greater than it base. Use an equation and the formula: area of a triangle= 0.5(base)(height) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114330 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> H=B+6<BR>\n" );
document.write( "A=BH/2<BR>\n" );
document.write( "13.5=B(B+6)/2<BR>\n" );
document.write( "13.5=(B^2+6B)/2<BR>\n" );
document.write( "2*13.5=B^2+6B<BR>\n" );
document.write( "B^2+6B-27=0<BR>\n" );
document.write( "(B+9)(B-3)=0<BR>\n" );
document.write( "B-3=0<BR>\n" );
document.write( "B=3 FOR THE BASE<BR>\n" );
document.write( "3+6=9 FOR THE HEIGHT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "13.5=(3*9)/2<BR>\n" );
document.write( "13.5=27/2<BR>\n" );
document.write( "13.5=13.5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );