document.write( "Question 2646: Factor completely: 36(x^4)y + 12(x^3)y^2 - 15(x^2)(y^3)\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "D. Scarfone \n" ); document.write( "
Algebra.Com's Answer #1143 by kiru_khandelwal(79)\"\" \"About 
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36(x^4)y + 12(x^3)y^2 - 15(x^2)(y^3)
\n" ); document.write( "=> taking out x^2 as common
\n" ); document.write( "=> 3x^2(12(x^2)y + 4xy^2 - 5y^3)
\n" ); document.write( "Taking out y as common factor
\n" ); document.write( "=> 3(x^2)y(12x^2 + 4xy - 5y^2) = 0
\n" ); document.write( "=> either x^2 = 0 => x = 0
\n" ); document.write( "or y = 0
\n" ); document.write( "or 12x^2 + 4xy - 5y^2 = 0
\n" ); document.write( "=> 12x^2 -6xy + 10xy - 5y^2 = 0
\n" ); document.write( "=> 6x(2x-y) + 5y(2x-y)=0
\n" ); document.write( "=> (6x+5y)(2x-y)=0
\n" ); document.write( "=> According to the zerp product rule
\n" ); document.write( "either 6x + 5y =0........equation(1)
\n" ); document.write( "or 2x -y =0 => y = 2x...........equatin(2)
\n" ); document.write( "substituting the value of y from equation(2) to equation(1)
\n" ); document.write( "=> 6x + 5y =0
\n" ); document.write( "=> 6x + 5(2x) = 0
\n" ); document.write( "=> 16x = 0 => x = 0
\n" ); document.write( "and since y = 2x = 0\r
\n" ); document.write( "\n" ); document.write( "So the only solution is x=0 and y=0 \n" ); document.write( "
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