document.write( "Question 155232: a piece of wire 42 cm long is bent into the shape of a rectangle whose width is twice its length. find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #114297 by nerdybill(7384) $\"\"$ $\"About$

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a piece of wire 42 cm long is bent into the shape of a rectangle whose width is twice its length. find the dimensions of the rectangle.
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\n" ); document.write( "Let x = length
\n" ); document.write( "then because: \"width is twice its length\"
\n" ); document.write( "2x = width
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\n" ); document.write( "Perimeter of ANY rectangle is:
\n" ); document.write( "2(length) + 2(width)
\n" ); document.write( "Or, in our case (plugging in our variables):
\n" ); document.write( "2x + 2(2x)
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\n" ); document.write( "Finally, since we had \"a piece of wire 42 cm long\" we get the formula of:
\n" ); document.write( "2x + 2(2x) = 42
\n" ); document.write( "2x + 4x = 42
\n" ); document.write( "6x = 42
\n" ); document.write( "x = 7 cm (length)
\n" ); document.write( "2x = 2(7) = 14 cm (width)
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