document.write( "Question 155218: find the first five terms in the expansion of (r-2s)^8, can somebody tell me how to find the coeffiecients. Thanks \n" ); document.write( "
Algebra.Com's Answer #114291 by stanbon(75887)\"\" \"About 
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find the first five terms in the expansion of (r-2s)^8, can somebody tell me how to find the coeffiecients.
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\n" ); document.write( "The form (a-b)^8 is 8C8a^8 + 8C7a^7(-b) + 8C6a^6(-b)^2 + 8C5a^5(-b)^3...
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\n" ); document.write( "Your Problem:
\n" ); document.write( "(r-(2s))^8= 8C8r^8 + 8C7r^7(-2s) + 8C6r^6(-2s)^2
\n" ); document.write( "+ 8C5r^5(-2s)^3 + 8C4r^4(-2s)^4 etc.
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\n" ); document.write( "The coefficients are:
\n" ); document.write( "1st : 1
\n" ); document.write( "2nd : 8*(-2) = -16
\n" ); document.write( "3rd: 28*(-2)^2 = 28*4 = 112
\n" ); document.write( "4th: 56*(-2)^3 = 56*(-8) = -448
\n" ); document.write( "5th: I'll leave this to you
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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