document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155202>Question 155202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Y=2X + 1 . Find the equation for the line that is perpendicular. I don't know where to begin. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114252 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=2X + 1 . Find the equation for the line that is perpendicular. I don't know where to begin.<BR>\n" );
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document.write( "The slope of the given equation is \"2\".<BR>\n" );
document.write( "The slope of ANY line perpendicular to it must be -1/2.<BR>\n" );
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document.write( "Such a line would be y = (-1/2)x<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2x%2B1%2C%28-1%2F2%29x%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2x%2B1%2C%28-1%2F2%29x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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