document.write( "Question 155189: HI!\r
\n" ); document.write( "\n" ); document.write( "I just started Algebra 2 this year, and we are reviewing from algebra right now, and I can not remember how to solve a problem where I am isolating a variable. The problem is:\r
\n" ); document.write( "\n" ); document.write( "x= 2y^2/5 +1
\n" ); document.write( "I am trying to get y alone.\r
\n" ); document.write( "\n" ); document.write( "the 2y^2 is all over 5, so its like a fraction. So far, I have put the 1 over with the x, so now it looks like\r
\n" ); document.write( "\n" ); document.write( "-1+x = 2y^2/5
\n" ); document.write( "Then I multipled the right side by 5, making that drop off, so now it looks like:\r
\n" ); document.write( "\n" ); document.write( "-1x= 2y^2. Now, I am stuck...How do I solve from here?
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Algebra.Com's Answer #114248 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
-1x= 2y^2.
\n" ); document.write( "(-1/2)x = y^2\r
\n" ); document.write( "\n" ); document.write( "y = sqrt[(-1/2)x] or y = -sqrt[(-1/2)x]\r
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\n" ); document.write( "Comment:
\n" ); document.write( "I doubt this is the answer you are looking for, but it is
\n" ); document.write( "the answer to the problem you have described.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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