document.write( "Question 22891: Wind resistance or atmospheric drag tends to slow down moving objects. Atmospheric drag varies jointly as an object's area \"A\" and velocity \"v\". If a car traveling at a speed of 50 mph with a surface area of 35Ftsquared experiences a drag of 192.5N (Newton’s), how fast must a car with 49ft squared surface area travel in order to experience a drag force of 247.94N?
\n" ); document.write( "A. 46 mph
\n" ); document.write( "B. 43 mph
\n" ); document.write( "C. 51 mph
\n" ); document.write( "D. 48 mph\r
\n" ); document.write( "\n" ); document.write( "B. 43 mph
\n" ); document.write( "C. 51 mph
\n" ); document.write( "D. 48 mph
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Algebra.Com's Answer #11424 by venugopalramana(3286)\"\" \"About 
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LET DRAG FORCE BE=F ,AREA=A,AND VELOCITY=V
\n" ); document.write( "F VARIES JOINTLY AS A AND V.THAT MEANS IT VARIES AS A*V
\n" ); document.write( "HENCE F=K*A*V…WHERE K IS A CONSTANT.
\n" ); document.write( "WE GOT FOR CASE 1….F=192.5=K*35*50..HENCE K=192.5/(50*35)=0.11
\n" ); document.write( "HENCE FOR CASE 2 ….F=247.94=0.11*49*V….V=247.94/(0.11*49)=46……A IS THE ANSWER
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