document.write( "Question 155144: How many solutions exist for a quadratic equation? How do we determine whether the solutions are real or complex? \n" ); document.write( "
Algebra.Com's Answer #114222 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "A quadratic polynomial can have 2 real solutions, 1 real solution, or 2 complex solutions. To determine whether the solutions are real or complex, simply use the discriminant formula. \r
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\n" ); document.write( "\n" ); document.write( "For example, to see if the equation \"2x%5E2%2B6x-10\" has real or complex solutions, let's use the discriminant formula\r
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\n" ); document.write( "\n" ); document.write( "From \"2x%5E2%2B6x-10\" we can see that \"a=2\", \"b=6\", and \"c=-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=b%5E2-4ac\" Start with the discriminant formula.\r
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\n" ); document.write( "\n" ); document.write( "\"D=%286%29%5E2-4%282%29%28-10%29\" Plug in a=2, b=6, and c=-10\r
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\n" ); document.write( "\n" ); document.write( "\"D=36-4%282%29%28-10%29\" Square 6 to get 36\r
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\n" ); document.write( "\n" ); document.write( "\"D=36--80\" Multiply 4(2)(-10) to get (8)(-10)=-80\r
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\n" ); document.write( "\n" ); document.write( "\"D=36%2B80\" Rewrite D=36--80 as D=36+80\r
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\n" ); document.write( "\n" ); document.write( "\"D=116\" Add 36 to 80 to get 116\r
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\n" ); document.write( "\n" ); document.write( "Since the discriminant is greater than zero, this means that there are two real solutions. So the quadratic has two real solutions\r
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