document.write( "Question 155122: How do I find the missing sides of the triangles when each trianlge measues 30,60,90 degrees and the leg is 8\r
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Algebra.Com's Answer #114209 by stanbon(75887)\"\" \"About 
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How do I find the missing sides of the triangles when each trianlge measues 30,60,90 degrees and the leg is 8
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\n" ); document.write( "That depends on whether the 8 is opposite the 30 or the 60 degree angle.
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\n" ); document.write( "If it is opposite the 30 degree angle, it is half the hypotenuse, so
\n" ); document.write( "the hypotenuse would have to be 16 and the 3rd side would have to be
\n" ); document.write( "sqrt[16^2 - 8^2]
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\n" ); document.write( "If is is opposite the 60 degree angle, the side opposite the 30 is \"x\"
\n" ); document.write( "and the hypotenuse is 2x.
\n" ); document.write( "Then (2x)^2 = x^2 + 8^2
\n" ); document.write( "3x^2 = 64
\n" ); document.write( "x^2 = 64/3
\n" ); document.write( "x = 8/sqrt(3)
\n" ); document.write( "2x = 16/sqrt(3)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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