document.write( "Question 22927: Amy travels 450 miles at a certain speed. If the car had gone 15mph faster, the trip would have taken one hour less. Find Amy's speed.
\n" ); document.write( "A. 78 mph
\n" ); document.write( "B. 75 mph
\n" ); document.write( "C. 68 mph
\n" ); document.write( "D. 72 mph
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Algebra.Com's Answer #11420 by venugopalramana(3286)\"\" \"About 
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LET AMY'S SPEED BE X MPH….TIME TO TRAVEL 450 MILES=450/X HRS.
\n" ); document.write( "IF CAR GOES 15 MPH FASTER SPEED = X+15…..TIME TO TRAVEL=450/(X+15)
\n" ); document.write( "THIS TIME IS 1 HOUR LESS.SO…450/X-450/(X+15)=1…MULTIPLYING BY LCM X(X+15)
\n" ); document.write( "450{X+15-X)=X(X+15)=450*15=6750=X^2+15X
\n" ); document.write( "X^2+15X-6750=0=X^2+90X-75X-6750=X(X+90)-75(X+90)=(X-75)(X+90).HENCE X=75….B IS THE ANSWER.
\n" ); document.write( "INCIDENTALLY I GOT THROUGH YAHOO 360 A MESSAGE REQUESTING HELP TO YOU FROM YOUR FATHER .I REPLIED IN AFFIRMATIVE TO YAHOO 360 AS I COULD NOT REPLY DIRECTLY O YOUR FATHER A I DONT HAVE HE MAIL ADDRESS.IF YOU GIVE THE ADDRES I CAN CLARIFY BYOUR OTHER DOUBTS TOO.
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