document.write( "Question 155014: The tens digit of a number is 3 less than the units digit. If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #114192 by ankor@dixie-net.com(22740)\"\" \"About 
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The tens digit of a number is 3 less than the units digit. If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3. What is the original number?
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\n" ); document.write( "Let x = the 10's digit; Let y = units digit
\n" ); document.write( "Then
\n" ); document.write( "10x+y = \"the number\"
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\n" ); document.write( "\"The tens digit of a number is 3 less than the units digit.\",therefore
\n" ); document.write( "x = (y-3)
\n" ); document.write( ":
\n" ); document.write( "\" If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3.
\n" ); document.write( ":
\n" ); document.write( "Subtract the remainder from the number and you have:
\n" ); document.write( "\"%28%2810x%2By%29-3%29%2F%28%28x%2By%29%29\" = 4
\n" ); document.write( ":
\n" ); document.write( "multiply both sides by (x+y)
\n" ); document.write( "10x + y - 3 = 4(x+y)
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\n" ); document.write( "10x + y - 3 = 4x + 4y
\n" ); document.write( "Arrange x on the left and y on the right with the remainder:
\n" ); document.write( "10x - 4x = 4y - y + 3
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\n" ); document.write( "6x = 3y + 3
\n" ); document.write( "Substitute (y-3) for x:
\n" ); document.write( "6(y-3) = 3y + 3
\n" ); document.write( ":
\n" ); document.write( "6y - 18 = 3y + 3
\n" ); document.write( ":
\n" ); document.write( "6y - 3y = 3 + 18
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\n" ); document.write( "3y = 21
\n" ); document.write( "y =\"21%2F3\"
\n" ); document.write( "y = 7
\n" ); document.write( "then
\n" ); document.write( "x = 7 -3
\n" ); document.write( "x = 4
\n" ); document.write( ":
\n" ); document.write( "47 = \"the number\"
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3.\"
\n" ); document.write( "\"47%2F%28%284%2B7%29%29\" = 4, remainder of 3
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