document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155003>Question 155003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rubbing alcohol is typically diluted with water to 70% strength. if you need 3.5 ounces of 45% rubbing alcohol, how many ounces of 70% rubbing alcohol and how much water should you combine? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114164 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=amount of 70% rubbing alcohol needed<BR>\n" );
document.write( "Then 3.5-x=amount of water needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure alcohol in the 70% solution (0.70x) plus the amount of pure alcohol in the water (0) has to equal the amount of pure alcohol in the final mixture (3.5*0.45).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.70x=3.5*0.45 or<BR>\n" );
document.write( "0.70x=1.575  divide each side by 0.70<BR>\n" );
document.write( "x=2.25 ounces-----------------------------amount of 70% alcohol needed<BR>\n" );
document.write( "3.5-x=3.5-2.25=1.25 ounces---------------- amount of water needed\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "2.25*0.70=3.5*0.45<BR>\n" );
document.write( "1.575=1.575\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
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