document.write( "Question 155059: An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #114162 by jim_thompson5910(35256)\"\" \"About 
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Note: The information \" leave Gray’s Lake at 3 P.M\" is extra information that is not helpful. So we can ignore the \"3 pm\"\r
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\n" ); document.write( "\n" ); document.write( "Let x = speed of local train \r
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\n" ); document.write( "\n" ); document.write( "Let's set up the equation for the local train:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance-rate-time equation\r
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\n" ); document.write( "\n" ); document.write( "\"50=%28x%29t\" Plug in \"d=50\" (the distance from the lake to Chicago) and \"r=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"50%2Fx=t\" Divide both sides by \"x\" to solve for \"t\"\r
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\n" ); document.write( "\n" ); document.write( "So the time \"t\" can be represented by \"t=50%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's set up the equation for the express train:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Go back to the distance-rate-time equation\r
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\n" ); document.write( "\n" ); document.write( "Since the \"express travels twice as fast as the local\", this means that the speed of the express train is \"2x\" mph. Also, because the express train \"arrives 1 hour ahead of\" the local train, this means that the time of the express train is \"t-1\" hours\r
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\n" ); document.write( "\n" ); document.write( "\"50=2x%28t-1%29\" Plug in \"d=50\", \"r=2x\" and replace \"t\" with \"t-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"50=2x%2850%2Fx-1%29\" Plug in \"t=50%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"50=2x%2850%2Fx%29-2x%281%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"50=100-2x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"-50=-2x\" Subtract 100 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"25=x\" Divide both sides by -2 to isolate \"x\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=25\". \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So the speed of the local train is 25 mph and the speed of the express train is 50 mph (since it is twice the speed of the local train)
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