document.write( "Question 155058: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #114160 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let n = # of nickels and d = # of dimes\r
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\n" ); document.write( "\n" ); document.write( "Since \"Joe has a collection of nickels and dimes that is worth $5.65\", this means that the first equation is \"0.05n%2B0.10d=5.65\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.05n%2B0.10d=5.65\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10d=565\" Multiply every term by 100 to move the decimal point two places to the right (effectively eliminating the decimal)\r
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\n" ); document.write( "\n" ); document.write( "Also, since \"the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45\", this tells us that \"0.05%28n%2B8%29%2B0.10%282d%29=10.45\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.05%28n%29%2B0.05%288%29%2B0.10%282d%29=10.45\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"0.05n%2B0.4%2B0.20d=10.45\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B40%2B20d=1045\" Multiply every term by 100 to move the decimal point two places to the right to make the decimal numbers whole.\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2Bcross%2840-40%29%2B20d=1045-40\" Subtract 40 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B20d=1005\" Subtract. So this is our second equation\r
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\n" ); document.write( "\n" ); document.write( "So we have the system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%285n%2B10d=565%2C5n%2B20d=1005%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10d=565\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"5n=565-10d\" Subtract \"10d\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "Notice how there's a \"5n\" in the second equation. So simply replace the \"5n\" in the second equation with \"565-10d\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28565-10d%29%2B20d=1005\" Plug in \"5n=565-10d\"\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2B565=1005\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2Bcross%28565-565%29=1005-565\" Subtract 565 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"10d=440\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"cross%2810%2F10%29d=440%2F10\" Divide both sides by 10\r
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\n" ); document.write( "\n" ); document.write( "\"d=44\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So Joe has 44 dimes.\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10d=565\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10%2844%29=565\" Plug in \"d=44\"\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B440=565\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"5n=125\" Subtract 440 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"n=25\" Divide both sides by 5 to isolate \"n\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So Joe has 25 nickels and 44 dimes
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