document.write( "Question 155032: The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How old is the meteorite? \n" ); document.write( "
Algebra.Com's Answer #114158 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How old is the meteorite? \n" ); document.write( ": \n" ); document.write( "The half-life formula: \n" ); document.write( "A = Ao*2^(-t/h) \n" ); document.write( "where: \n" ); document.write( "Ao = initial amt (= 1 in this problem) \n" ); document.write( "A = resulting amt (decimal equiv of %) \n" ); document.write( "t = time (in millions of years here) \n" ); document.write( "h = half-life of the substance (millions of years) \n" ); document.write( ": \n" ); document.write( ".076 = 1*2^(-t/4.2) \n" ); document.write( "or \n" ); document.write( "2^(-t/4.2) = .076 \n" ); document.write( ": \n" ); document.write( "Find the nat log of both sides: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply: \n" ); document.write( "-.693147t = 4.2 * -2.577022 \n" ); document.write( ": \n" ); document.write( "-.693147t = -10.8235 \n" ); document.write( "t = \n" ); document.write( "t = 15.615 million years old \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution on a calc: enter 2^(-15.615/4.2) = .075999 ~ .076 or 7.6% \n" ); document.write( " \n" ); document.write( " |