document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155012>Question 155012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store manager wishes to reduce the price on his fresh ground coffee by mixing 2 grades. If he has 50 pounds of coffee which sells for $5 per pound, how much coffee worth $3 per pound must he mix with it so that he can sell the final mixture for $4.25 per pound?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114147 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50*5+3x=4.25(50+x)<BR>\n" );
document.write( "250+3x=212.5+4.25x<BR>\n" );
document.write( "3x-4.25x=212.5-250<BR>\n" );
document.write( "-1.25x=-37.5<BR>\n" );
document.write( "x=-37.5/-1.25<BR>\n" );
document.write( "x=30 pounds of $3 coffee is required.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "50*5+3*30=4.25(50+30)<BR>\n" );
document.write( "250+90=4.25*80<BR>\n" );
document.write( "340=340 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );