document.write( "Question 155037: algebra of linear and quadratic expressions.\r
\n" ); document.write( "\n" ); document.write( "find the values of k for which the quadratic 2x^2+kx+9=0 has one real solution, and another with no real solutions. \r
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Algebra.Com's Answer #114144 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"D=b%5E2-4ac\" Start with the discriminant formula\r
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\n" ); document.write( "\n" ); document.write( "\"D=k%5E2-4%282%29%289%29\" Plug in \"a=2\", \"b=k\" and \"c=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=k%5E2-8%289%29\" Multiply 4 and 2 to get 8\r
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\n" ); document.write( "\n" ); document.write( "\"D=k%5E2-72\" Multiply 8 and 9 to get 72\r
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\n" ); document.write( "\n" ); document.write( "So we'll use the equation \"D=k%5E2-72\" to solve the following:\r
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\n" ); document.write( "\n" ); document.write( "1) \"find the values of k for which the quadratic \"2x%5E2%2Bkx%2B9=0\" has one real solution\"\r
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\n" ); document.write( "\n" ); document.write( "If a quadratic has one real solution, then the discriminant is equal to zero. So this means that \"D=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=k%5E2-72\" Start with the previous equation\r
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\n" ); document.write( "\n" ); document.write( "\"0=k%5E2-72\" Plug in \"D=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"72=k%5E2\" Add 72 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0%2B-sqrt%2872%29=k\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"k=sqrt%2872%29\" or \"k=-sqrt%2872%29\" Break up the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"k=2%2Asqrt%2818%29\" or \"k=-2%2Asqrt%2818%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "So if \"k=2%2Asqrt%2818%29\" or \"k=-2%2Asqrt%2818%29\", then the discriminant is equal to zero. This means that the equation \"2x%5E2%2B2%2Asqrt%2818%29x%2B9=0\" or \"2x%5E2-2%2Asqrt%2818%29x%2B9=0\" only has one real solution.\r
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\n" ); document.write( "\n" ); document.write( "2) \"find the values of k for which the quadratic \"2x%5E2%2Bkx%2B9=0\" no real solutions\"\r
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\n" ); document.write( "\n" ); document.write( "If a quadratic has no real solutions, this means that the discriminant is less than zero. In other words, \"D%3C0\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=k%5E2-72\" Go back to the previous equation\r
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\n" ); document.write( "\n" ); document.write( "\"k%5E2-72%3C0\" Since \"D%3C0\", this means that the right side is less than zero\r
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\n" ); document.write( "\n" ); document.write( "\"k%5E2%3C72\" Add 72 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"k%3C0%2B-sqrt%2872%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"k%3Csqrt%2872%29\" or \"k%3E-sqrt%2872%29\" Break up the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"k%3C2%2Asqrt%2818%29\" or \"k%3E-2%2Asqrt%2818%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"-2%2Asqrt%2818%29%3Ck%3C2%2Asqrt%2818%29\" Recombine the two inequalities to form one compound inequality\r
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\n" ); document.write( "\n" ); document.write( "So if \"k\" is in between \"-2%2Asqrt%2818%29\" and \"2%2Asqrt%2818%29\", then the discriminant is less than zero. This means that if \"k\" is in between \"-2%2Asqrt%2818%29\" and \"2%2Asqrt%2818%29\", then the quadratic \"2x%5E2%2Bkx%2B9=0\" will have no solutions\r
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