document.write( "Question 155026: Find the horizontal asymptote, if any, of the graph of the rational function.\r
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document.write( "f(x)=8x/2x^2+1\r
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document.write( "a. y=1/4
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document.write( "b. y=0
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document.write( "c. y=4
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document.write( "d. no horizontal asymptote \n" );
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Algebra.Com's Answer #114131 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! No horizontal awymptote because 2x^2+1=0 has no Real Number solution. \n" ); document.write( "----------------- \n" ); document.write( "Another way to look at it: That 2x^2 term can never be negative. \n" ); document.write( "When you add 1 to it you always get a positive number---never zero. \n" ); document.write( "----------------- \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |