document.write( "Question 155010: A hospital needs to dilute a 60% boric acid solution to a 10% solution. If it needs 40 liters of the 10% solution, how much of the 40% solution and how much water should it use? For some reason i always come up with a negative 24 and that isn't right. \n" ); document.write( "
Algebra.Com's Answer #114127 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
I THINK YOU NEED TO RECHECK YOUR PROBLEM. I THINK THE \"40%\" SHOULD BE \"60%\". ANYWAY, I WILL MAKE THAT ASSUMPTION.\r
\n" ); document.write( "\n" ); document.write( "Let x=amount of 60% solution needed
\n" ); document.write( "Then 40-x=amount of water needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure boric acid in the water(0) plus the amount of pure boric acid in the 60% solution (0.60x) has to equal the amount of pure boric acid in the final mixture(0.10*40). So our equatuion to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.60x=0.10*40
\n" ); document.write( "0.60x=4 divide each side by 0.60
\n" ); document.write( "x=6.67 liters --------------of the 60% solution
\n" ); document.write( "40-x=40-6.67=33.33 liters-------------of water\r
\n" ); document.write( "\n" ); document.write( "Ck
\n" ); document.write( "6.67*0.60=40*0.10
\n" ); document.write( "4=4\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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