document.write( "Question 154741This question is from textbook college algebra ninth edition
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document.write( ": One morning, John drove 5 hours before stoping to eat. After lunch, he increased his speed by 10 mph. If he completed a 430-mile trip in 8 hours of driving time, how fast did he drive in the morning? \n" );
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Algebra.Com's Answer #114101 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! One morning, John drove 5 hours before stopping to eat. After lunch, he \n" ); document.write( "increased his speed by 10 mph. If he completed a 430-mile trip in 8 hours of \n" ); document.write( "driving time, how fast did he drive in the morning? \n" ); document.write( ": \n" ); document.write( "Let s = his speed in the morning \n" ); document.write( "then \n" ); document.write( "(s+10) = his speed in the afternoon \n" ); document.write( "; \n" ); document.write( "A total of 8 hrs driving time, if he drove 5 hrs in the morning, \n" ); document.write( "He drove 3 hrs in the afternoon \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Dist = time * speed \n" ); document.write( ": \n" ); document.write( "Morning miles + afternoon miles = 430 miles \n" ); document.write( "5s + 3(s+10) = 430 \n" ); document.write( "; \n" ); document.write( "5s + 3s + 30 = 430 \n" ); document.write( ": \n" ); document.write( "8s = 430 - 30 \n" ); document.write( "s = \n" ); document.write( "s = 50 mph in the morning \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distance at the two speeds: \n" ); document.write( "5(50) + 3(60) = \n" ); document.write( "250 + 180 = 430 \n" ); document.write( " \n" ); document.write( " |