document.write( "Question 154884: Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 11%. His total annual income from the two investments was $3990. How much was invested at 11%? \n" ); document.write( "
Algebra.Com's Answer #114097 by ankor@dixie-net.com(22740)\"\" \"About 
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Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 11%. His total annual income from the two investments was $3990. How much was invested at 11%?
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\n" ); document.write( "Let x = amt invested at 7%
\n" ); document.write( ":
\n" ); document.write( "It said,\"invested $2000 more than twice this amount at 11%.\" therefore
\n" ); document.write( "(2x+2000) = amt invested at 11%
\n" ); document.write( ":
\n" ); document.write( "Write an income equation:
\n" ); document.write( "7% income + 11% income = $3990
\n" ); document.write( ":
\n" ); document.write( ".07x + .11(2x+2000) = 3990
\n" ); document.write( ":
\n" ); document.write( ".07x + .22x + 220 = 3990
\n" ); document.write( ":
\n" ); document.write( ".29x = 3990 - 220
\n" ); document.write( ":
\n" ); document.write( ".29x = 3770
\n" ); document.write( "x = \"3770%2F.29\"
\n" ); document.write( "x = $13000 invested at 7%
\n" ); document.write( ":
\n" ); document.write( "Find amt invested at 11%
\n" ); document.write( "2(13000) + 2000 =
\n" ); document.write( "26000 + 2000 = $28000 invested at 11%
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\n" ); document.write( ":
\n" ); document.write( "Check solution
\n" ); document.write( ".07(13000) + .11(28000) =
\n" ); document.write( "910 + 3080 = 3990; confirms our solution \n" ); document.write( "
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