document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154970>Question 154970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The differance of the measures of two supplementary angles is 56 degrees. Find the measure of each of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114095 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The differance of the measures of two supplementary angles is 56 degrees. Find the measure of each of the angles<BR>\n" );
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document.write( "Supplementary means the add up to 180 degs.<BR>\n" );
document.write( "A + B = 180<BR>\n" );
document.write( "A - B = 56<BR>\n" );
document.write( "Add the 2 eqns.<BR>\n" );
document.write( "2A = 236<BR>\n" );
document.write( "A = 118 degs<BR>\n" );
document.write( "So B = 180 - A<BR>\n" );
document.write( "B = 62 degs<BR>\n" );
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